Concentration of Iodine Atoms in Photodissociation of Ethyl Iodide

Question:

Calculate the concentration (in molecules cm−3 ) of iodine atoms when an excimer laser pulse of 10 mJ at 248 nm is incident on a cubical cell of volume 1 cm3 containing 3 × 1015 molecules cm−3 of ethyl iodide:

    C2 H5 I → C2 H5 + I

The absorption coefficient of ethyl iodide at 248 nm is = 63 L/mole/cm. (What assumption do you need to make about the quantum yield for this photodissociation?)

This is the problem 7.21 of the book “Chemical Kinetics and Reaction Dynamics, written by Paul L. Houston”.

Solution:
Absorption fraction of photons is given by,

…………………………………………………………………………………………………………………………………………………………………………………………………………………..

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